Nernst Equation MCQ Quiz - Objective Question with Answer for Nernst Equation - Download Free PDF
Last updated on Apr 7, 2025
Latest Nernst Equation MCQ Objective Questions
Nernst Equation Question 1:
Calculate the emf of a cell at 298 K for the reaction:
Ni(s) + 2Ag+ → Ni2+ + 2Ag(s)
(Ecell∘ = 1.05 V, [Ag+] = 0.001 M, [Ni2+] = 0.160 M)
Answer (Detailed Solution Below)
Nernst Equation Question 1 Detailed Solution
CONCEPT:
Nernst Equation
Ecell = Eocell − (0.059/n) log(Q)
- The cell potential under non-standard conditions is calculated using the Nernst equation:
- Where:
- Ecell = Cell potential at non-standard conditions
- Eocell = Standard cell potential
- n = Number of moles of electrons transferred in the reaction
- Q = Reaction quotient, given by the ratio of the concentrations of products to reactants raised to the power of their stoichiometric coefficients.
EXPLANATION:
- For the reaction:
Ni(s) + 2Ag+(aq) → Ni2+(aq) + 2Ag(s)
- n = 2 (number of electrons transferred)
- Reaction quotient (Q):
Q = [Ni2+]/([Ag+]2)
Q = 0.160 / (0.001)2 = 0.160 / 0.000001 = 160,000
- Using the Nernst equation:
Ecell = Eocell − (0.059/2) log(Q)
Ecell = 1.05 − (0.059/2) log(160,000)
Ecell = 1.05 − 0.0295 × log(160,000)
Ecell = 1.05 − 0.0295 × 5.204 (log of 160,000)
Ecell = 1.05 − 0.1536
Ecell = 0.89 V
Therefore, the calculated cell emf is approximately 0.90 V.
Nernst Equation Question 2:
Using the Nernst equation for the cell reaction,
Pb + Sn2+ → Pb2+ + Sn
The ratio of [Pb2+][Sn2+]\frac{[\text{Pb}^{2+}]}{[\text{Sn}^{2+}]} is _____x 109 for which Ecell=0E_{\text{cell}} = 0.
(Given: EPb2+/Pb∘=0.13 VE^\circ_{\text{Pb}^{2+}/\text{Pb}} = 0.13 \, \text{V} and ESn2+/Sn∘=−0.14 VE^\circ_{\text{Sn}^{2+}/\text{Sn}} = -0.14 \, \text{V}).
Answer (Detailed Solution Below) 1.73 - 1.76
Nernst Equation Question 2 Detailed Solution
CONCEPT:
Nernst Equation for Cell Potential Calculation
- The Nernst equation is used to calculate the cell potential under non-standard conditions.
- The equation relates the standard electrode potential to the actual potential based on the concentrations of the reactants and products.
- The Nernst equation is given as:
- Where
is the actual cell potential, is the standard cell potential, n is the number of electrons transferred, and Q is the reaction quotient.
CALCULATION:
- For the reaction:
- Given:
- Standard reduction potential of
- Standard reduction potential of
- Standard reduction potential of
- Using the Nernst equation for a reaction where
: - Hence, the ratio
.
The ratio of
Nernst Equation Question 3:
The thermodynamic efficiency of cell is given by
Answer (Detailed Solution Below)
Nernst Equation Question 3 Detailed Solution
Nernst Equation Question 4:
To calculate the solubility product of AgI, the following cell was constructed
Ag | Ag+, I– || AgI(s) | Ag
If Eo is the standard electrode potential, then Ksp is given as
Answer (Detailed Solution Below)
Nernst Equation Question 4 Detailed Solution
Nernst Equation Question 5:
The reduction electrode potential for the electrode Pt | Tl3+, Tl+ may be written as
Answer (Detailed Solution Below)
Nernst Equation Question 5 Detailed Solution
Top Nernst Equation MCQ Objective Questions
Electrode potential for Mg electrode varies according to the equation
The graph of
Answer (Detailed Solution Below)
Nernst Equation Question 6 Detailed Solution
Download Solution PDFCorrect answer: 2)
concept:
- Electrode Potential: The potential difference which facilitates the flow of electrons between two phases is called electrode potential.
- Depending on whether oxidation or reduction has occurred, the electrode potential will be designated as an oxidation or reduction potential.
- The greater the value of electrode potential, the greater is the tendency to react.
- The electrode potential at any concentration measured with respect to the standard electrode can be given by the Nernst equation
EXPLANATION:
- The given equation is Nernst equation.
- Here is the cell potential at the given concentration.
- Log [Mg2+] is the logarithm of the concentration of ion Mg2+.
- They are directly proportional to each other because increase in concentration increases the cell potential.
- The given equation is equivalent to the equation of the straight line y = = mx + c. Therefore the graph will be a straight line with a y-intercept and a positive slope of 0.059/2.
- The equation is arranged in the form y = mx+c.
conclusion:
Thus, the graph of
Which of the following statement is correct?
Answer (Detailed Solution Below)
Nernst Equation Question 7 Detailed Solution
Download Solution PDFCONCEPT:
Intensive and Extensive Properties
- Intensive properties are those that do not depend on the amount of matter or the size of the system. Examples include temperature, density, and cell potential (Ecell).
- Extensive properties are those that do depend on the amount of matter or the size of the system. Examples include mass, volume, and Gibbs free energy change (∆rG) of the cell reaction.
EXPLANATION:
- The cell potential (Ecell) is an intensive property because it is a measure of the potential difference between two electrodes, and it does not depend on the amount of material in the system.
- The Gibbs free energy change (∆rG) of the cell reaction is an extensive property because it depends on the amount of reactants and products in the reaction.
Therefore, the correct statement is: Ecell is an intensive property while ∆rG of cell reaction is an extensive property.
Nernst Equation Question 8:
Electrode potential for Mg electrode varies according to the equation
The graph of
Answer (Detailed Solution Below)
Nernst Equation Question 8 Detailed Solution
Correct answer: 2)
concept:
- Electrode Potential: The potential difference which facilitates the flow of electrons between two phases is called electrode potential.
- Depending on whether oxidation or reduction has occurred, the electrode potential will be designated as an oxidation or reduction potential.
- The greater the value of electrode potential, the greater is the tendency to react.
- The electrode potential at any concentration measured with respect to the standard electrode can be given by the Nernst equation
EXPLANATION:
- The given equation is Nernst equation.
- Here is the cell potential at the given concentration.
- Log [Mg2+] is the logarithm of the concentration of ion Mg2+.
- They are directly proportional to each other because increase in concentration increases the cell potential.
- The given equation is equivalent to the equation of the straight line y = = mx + c. Therefore the graph will be a straight line with a y-intercept and a positive slope of 0.059/2.
- The equation is arranged in the form y = mx+c.
conclusion:
Thus, the graph of
Nernst Equation Question 9:
Calculate the emf of a cell at 298 K for the reaction:
Ni(s) + 2Ag+ → Ni2+ + 2Ag(s)
(Ecell∘ = 1.05 V, [Ag+] = 0.001 M, [Ni2+] = 0.160 M)
Answer (Detailed Solution Below)
Nernst Equation Question 9 Detailed Solution
CONCEPT:
Nernst Equation
Ecell = Eocell − (0.059/n) log(Q)
- The cell potential under non-standard conditions is calculated using the Nernst equation:
- Where:
- Ecell = Cell potential at non-standard conditions
- Eocell = Standard cell potential
- n = Number of moles of electrons transferred in the reaction
- Q = Reaction quotient, given by the ratio of the concentrations of products to reactants raised to the power of their stoichiometric coefficients.
EXPLANATION:
- For the reaction:
Ni(s) + 2Ag+(aq) → Ni2+(aq) + 2Ag(s)
- n = 2 (number of electrons transferred)
- Reaction quotient (Q):
Q = [Ni2+]/([Ag+]2)
Q = 0.160 / (0.001)2 = 0.160 / 0.000001 = 160,000
- Using the Nernst equation:
Ecell = Eocell − (0.059/2) log(Q)
Ecell = 1.05 − (0.059/2) log(160,000)
Ecell = 1.05 − 0.0295 × log(160,000)
Ecell = 1.05 − 0.0295 × 5.204 (log of 160,000)
Ecell = 1.05 − 0.1536
Ecell = 0.89 V
Therefore, the calculated cell emf is approximately 0.90 V.
Nernst Equation Question 10:
The thermodynamic efficiency of cell is given by
Answer (Detailed Solution Below)
Nernst Equation Question 10 Detailed Solution
Nernst Equation Question 11:
The entropy change (ΔS) for a cell reaction is given by
Answer (Detailed Solution Below)
Nernst Equation Question 11 Detailed Solution
Nernst Equation Question 12:
The e.m.f. of the following three galvanic cells:
I. Zn | Zn2+ (1 M) || Cu+2 (1 M) | Cu
II. Zn | Zn2+ (0.1 M) || Cu2+ (1 M) | Cu
III. Zn | Zn2+ (1 M) || Cu2+ (0.1 M) | Cu
are represented by E1, E2 and E3. Which of the following statement is true?
Answer (Detailed Solution Below)
Nernst Equation Question 12 Detailed Solution
Concept:
The electromotive force (e.m.f.) of a galvanic cell depends on the concentration of the ions involved in the redox reactions. This relationship is given by the Nernst equation, which adjusts the standard electrode potentials based on ion concentrations.
Nernst equation:
At Room temperature(T = 298K), Equation becomes:
Explanation:
The standard cell potential (Ecell) for a zinc-copper galvanic cell can be calculated using the standard reduction potentials and the Nernst equation:
1. Standard reduction potentials at 25°C are:
- Zn2+ + 2e– → Zn: E° = -0.76 V
- Cu2+ + 2e– → Cu: E° = +0.34 V
The standard e.m.f. (E°) for cell I is given by:
E°cell = E°cathode - E°anode
E°I = 0.34 V - (-0.76 V) = 1.10 V
Using the Nernst equation for different ion concentrations:
Where Q is the reaction quotient:
- For cell II: Q =
= - For cell III: Q =
=
Considering the effect of ion concentration:
- Cell II:
≈ 1.13 V
- Cell III:
= ≈ 1.07 V
Thus, the e.m.f. values are in the order E2 > E1 > E3.
Conclusion:
Based on the Nernst equation and given conditions, the true statement is: E2 > E1 > E3
Nernst Equation Question 13:
The reduction electrode potential for the electrode Pt | Tl3+, Tl+ may be written as
Answer (Detailed Solution Below)
Nernst Equation Question 13 Detailed Solution
Nernst Equation Question 14:
If 2.303 RT/F = 0.059 and the activities of the solids are constant, then e.m.f. of the cell
Zn | Zn2+ (a1) || Cu2+ (a2) | Cu is
Answer (Detailed Solution Below)
Nernst Equation Question 14 Detailed Solution
Nernst Equation Question 15:
The correct value of Eº, of a half cell in the following graph of E vs log m(molality) is:
Answer (Detailed Solution Below)
Nernst Equation Question 15 Detailed Solution
The correct answer is BB'
Concept:-
- The Nernst equation is an important relation in the field of electrochemistry that is used to calculate the potential of an electrochemical reaction (also known as a half-cell or a full-cell reaction). It establishes the relationship between electric potential (or electromotive force, E) and the concentrations of reactants and products. Named after Walther Nernst, a German scientist, the equation is given by:
- E = E° - (RT/nF) x lnQ
where,
E is the cell potential (E_cell) or emf of the cell at non-standard conditions (the conditions you are working with)
E° is the standard cell potential or standard emf of the cell (at standard conditions: 25°C, 1M concentrations for all particles, 1atm pressure for all gases)
R is the gas constant, which equals 8.314 J/(mol-K)
T is the absolute temperature in Kelvin (Kelvin = degrees Celsius + 273.15)
n is the number of moles of electrons (e-) transferred in the balanced redox reaction
F is Faraday’s constant, the amount of electric charge in one mole of electrons, approximately 96485 C/mol (Coulombs per mole)
Q is the reaction quotient, essentially equal to the concentration ratio of the products divided by reactants. It becomes the equilibrium constant (K) when the system is at equilibrium.
- An important note is that the term RT/nF is often replaced with 0.0592/n at room temperature (25°C) when E is measured in volts, yielding a simplified form of the Nernst equation:
- E = E° - (0.0592/n) x logQ
- This equation gives you the voltage that will actually be measured in a real-world cell, taking into account the non-standard conditions that often prevail (such as the non-ideal temperature, and concentrations or pressures).
Explanation:-.
According to the formula of the nernst equation,
Ecell = Eocell - (0.059/ncell ) × log m
This equation is a linear curve, as we can see from the graph. So rewriting it in the form of an equation of line.
Y = mx + c
Where, y = Ecell , m = 0.059/ncell and c = Eocell
So, we find that Eocell is the intercept of the graph which is BB'.
Ans. BB' is the correct value of Eocell.