Euler's Theory of Buckling MCQ Quiz in मराठी - Objective Question with Answer for Euler's Theory of Buckling - मोफत PDF डाउनलोड करा

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पाईये Euler's Theory of Buckling उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). हे मोफत डाउनलोड करा Euler's Theory of Buckling एमसीक्यू क्विझ पीडीएफ आणि बँकिंग, एसएससी, रेल्वे, यूपीएससी, स्टेट पीएससी यासारख्या तुमच्या आगामी परीक्षांची तयारी करा.

Latest Euler's Theory of Buckling MCQ Objective Questions

Top Euler's Theory of Buckling MCQ Objective Questions

Euler's Theory of Buckling Question 1:

The buckling load for a column hinged at both ends is 20 kN. What will be the buckling load when both ends are fixed?

  1. 800 kN
  2. 400 kN
  3. 80 kN
  4. 40 kN

Answer (Detailed Solution Below)

Option 3 : 80 kN

Euler's Theory of Buckling Question 1 Detailed Solution

Concepts:

Buckling load for the column,

Where,

Pe = Buckling load, Imin = Moment of inertia about centroids axis, Le = Effective length.

Effective length (Le),

When both ends of the column hinged (Le) = L

When both ends of the column fixed (Le) = 

Calculation:

Given:

Buckling load for both ends hinged = 20kN and L= L

  = 20 kN.

Then, buckling load for the column when both ends fixed and L

Pe= 4 × 20 = 80 kN.

Euler's Theory of Buckling Question 2:

The piston rod of diameter 20 mm and length 700 mm in hydraulic cylinder is subjected to compressive force of 10 kN due to the internal pressure. The end conditions for the rod may be assumed as guided at the piston end and hinged at the other end. The Young’s modulus is 200 GPa. The factor of safety for the piston rod is 

  1. 6.32
  2. 2.75
  3. 5.62
  4. 11.0

Answer (Detailed Solution Below)

Option 1 : 6.32

Euler's Theory of Buckling Question 2 Detailed Solution

Concept:

Euler’s crippling load:

Assuming the guided end to be fixed and the other end is given as hinged. Euler’s crippling load formula is used to find the buckling load of long columns.

It is given by

Where E = Modulus of elasticity, I = moment of inertia, leff = Effective length of the column

The Effective length of the column depending on ends conditions is as follows:

End Condition

Both ends hinged

One end is fixed other free

Both ends fixed

One end was fixed and the other hinged

Effective length (Le)

L

2L

L/2

L/ √2

Calculations:

Given : Diameter (d) = 20 mm

Length (L) = 700 mm

Force (P) = 10 kN (compressive)

Assuming guided end to be fixed and other end given as hinged. The crippling load according to Euler’s equation.

Factor of safety 

Euler's Theory of Buckling Question 3:

Which of the following is NOT an assumption in Euler’s theory?

  1. Column will fail by buckling only.
  2. The self-weight of the column is negligible.
  3. The cross-section of a column is uniform throughout the length.
  4. The direct stress is very large as compared to the bending stress.

Answer (Detailed Solution Below)

Option 4 :
The direct stress is very large as compared to the bending stress.

Euler's Theory of Buckling Question 3 Detailed Solution

Explanation:

According to Euler's column theory, the crippling load for a column of length L,

Where Leq is the effective length of the column.

The following assumptions are made in Euler's column theory:

  • The column is initially straight and load is applied axially
  • The cross-section of the column is uniform throughout its length
  • The column material is perfectly elastic, homogeneous and isotropic and obeys Hooke’s law
  • The length of the column is very large as compared to its lateral dimensions
  • The direct stress is very small as compared to the bending stress
  • The column will fail by buckling alone
  • The self-weight of the column is negligible

Euler's Theory of Buckling Question 4:

Euler's formula is applicable for which type of columns? 

  1.  Weak columns 
  2.  Long columns  
  3. Short columns
  4.  Strong columns  

Answer (Detailed Solution Below)

Option 2 :  Long columns  

Euler's Theory of Buckling Question 4 Detailed Solution

Explanation:

Columns and Struts:

A structural member, subjected to an axial compressive force, is called a strut. A strut may be horizontal, inclined or even vertical. But a vertical strut, used in buildings or frames, is called a column.

According to Euler's column theory, the critical load (P) on the column for different types of end conditions is as follows:

Where Pe = Buckling load, Imin = Minimum of [Ixx & Iyy], L = Actual length of the column, α = Length fixity coefficient, n = End fixity coefficient 

Le = αL and 

Euler's formula holds good only for long columns.

The Length fixity coefficient and End fixity coefficient for the given end conditions are given in the following table:

S.No.

End Conditions

Length fixity coefficient (α)

End fixity coefficient

1.

Both ends hinged

1

1

2.

One end fixed and the other end free

2

3.

Both ends fixed

4

4.

One end fixed and the other end hinged

2

Additional Information

(1) The vertical column will have two moments of inertia (i.e. Ixx and Iyy). Since the column will tend to buckle in the direction of the least moment of inertia, therefore the least value of the two moments of inertia is to be used in Euler's formula.

(2) Euler's formula is given by

∵  I = Ak2,

Where A is the area and k is the least radius of gyration of the section

(3) The ratio (L/k) is known as the slenderness ratio.

(4) Sometimes, the columns whose slenderness ratio is more than 80, are known as long columns, and those whose slenderness ratio is less than 80 are known as short columns.

(5) Euler's formula holds good only for long columns.

(6) For short or long columns Rankine’s Formula is used.

Euler's Theory of Buckling Question 5:

 In beam-columns or eccentric loaded columns, an elastic critical stress in compression fcc is

Where: E = Modulus of elasticity of steel

λ = Slenderness ratio in the plane of bending

Answer (Detailed Solution Below)

Option 2 :

Euler's Theory of Buckling Question 5 Detailed Solution

Concept:

Elastic critical load in columns is given by Euler’s Formula which is,  

Where, is the critical load of the column, E is the modulus of elasticity of the column, I is the moment of inertia of the column cross section,  is the effective length of the column.

Now, effective length (Le) for different end conditions in terms of actual length (L) are listed in the following table:

Support Conditions

Effective length (Le)

Both ends hinged/pinned

Le = L

One end hinged other end fixed

Le = L/√2

Both ends fixed

Le = L/2

One end fixed and other end free

Le = 2L


Now, moment of inertia can be expressed as,  where A is the cross sectional area of the column and r is the radius of gyration for the column cross section.

 where λ is slenderness ratio.

∴ Elastic critical stress, 

Euler's Theory of Buckling Question 6:

The crippling load taken by a column with both ends hinged is 100 kN. The crippling load taken by the same column with one end fixed and other end free will be:

  1. 400 kN
  2. 100 kN
  3. 50 kN
  4. 25 kN

Answer (Detailed Solution Below)

Option 4 : 25 kN

Euler's Theory of Buckling Question 6 Detailed Solution

Concept:

The maximum load at which the column tends to have lateral displacement or tends to buckle is known as buckling or crippling load. Load columns can be analysed with the Euler’s column formulas can be given as

End Condition

Both ends hinged

One end fixed other free

Both ends fixed

One end fixed and the other hinged

Effective length (Le)

L

2L

1/2

 

Calculation:

P1 = both ends hinged = 100 kN, P2 = one end fixed and other end free

P ∝ 1/Leq2

∴ P2 = 25 kN

 

 

Euler's Theory of Buckling Question 7:

For a long slender column of uniform cross section, the ratio of critical buckling load for the case with both ends hinged to the case with both ends clamped is

  1. 0.25
  2. 4.0
  3. 0.125
  4. 0.5

Answer (Detailed Solution Below)

Option 1 : 0.25

Euler's Theory of Buckling Question 7 Detailed Solution

Concept:

Euler’s critical buckling load 

Where, Imin = minimum area moment of Inertia, E = young’s modulus of elasticity, Le = Equivalent length = L ⋅ α

α for different loading conditions are different

Calculation:

Given:

Two columns,

both ends are fixed, Le = L × 0.5 

both ends are hinged Le = L × 1

Euler's Theory of Buckling Question 8:

A steel column of rectangular section (15 mm × 10 mm) and length 1.5 m is simply supported at both ends. Assuming modulus of elasticity, E = 200 GPa for steel, the critical axial load (in kN) is ____ (correct to two decimal places).

Answer (Detailed Solution Below) 1.00 - 1.20

Euler's Theory of Buckling Question 8 Detailed Solution

Concept:

Long Column

Critical Load

Both ends are hinged

One end fixed, and another end is free

Both ends are fixed

one end fixed & fixed and another end is hinged

Calculation:

A steel column is simply supported at both ends means it is a case of both ends hinged:

Given: b = 15 mm, d = 10 mm, L = 1.5 m = 1500 mm, E = 200 GPa = 200 × 1000 MPa

Euler's Theory of Buckling Question 9:

The highest buckling load will be for ________.

  1. column with one end fixed and other end free
  2. column with one end fixed and other end hinged
  3. column with both ends fixed
  4. column with both ends hinged

Answer (Detailed Solution Below)

Option 3 : column with both ends fixed

Euler's Theory of Buckling Question 9 Detailed Solution

Concept:

The maximum load at which the column tends to have lateral displacement or tends to buckle is known as buckling or crippling load. Load columns can be analysed with the Euler’s column formulas can be given as

  • For both end hinged, n=1
  • For one end fixed and other free, n=1/2
  • For both end fixed, n=2
  • For one end fixed and other hinged, n=√2

Effective Length:

Application:

nFixed-Fixed > nFixed-Hinged > nHing-Hing > nFixed-Free

PFixed-Fixed > PFixed-Hinged > PHing-Hing > PFixed-Free

So highest buckling load will be when both end fixed.

Euler's Theory of Buckling Question 10:

Which of the following assumptions is INCORRECT about the long column?

  1. The column behaves elastically. 
  2. The load acts perfectly axial and passes through the centroid of the column section.
  3. The weight of the column is neglected.
  4. The material is non - homogeneous and anisotropic.

Answer (Detailed Solution Below)

Option 4 : The material is non - homogeneous and anisotropic.

Euler's Theory of Buckling Question 10 Detailed Solution

The following assumptions are made in the Euler’s column theory about long column:

  • The column is initially perfectly straight, and the load is applied axially
  • The cross-section of the column is uniform throughout its length
  • The column material is perfectly elastic, homogeneous and isotropic and obeys Hooke’s law
  • The length of the column is very large as compared to its lateral dimensions
  • The direct stress is very small as compared to the bending stress.
  • The column will fail by buckling alone
  • The self-weight of the column is negligible

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