Euler's Theory of Buckling MCQ Quiz in मराठी - Objective Question with Answer for Euler's Theory of Buckling - मोफत PDF डाउनलोड करा
Last updated on Mar 24, 2025
Latest Euler's Theory of Buckling MCQ Objective Questions
Top Euler's Theory of Buckling MCQ Objective Questions
Euler's Theory of Buckling Question 1:
The buckling load for a column hinged at both ends is 20 kN. What will be the buckling load when both ends are fixed?
Answer (Detailed Solution Below)
Euler's Theory of Buckling Question 1 Detailed Solution
Concepts:
Buckling load for the column,
Where,
Pe = Buckling load, Imin = Moment of inertia about centroids axis, Le = Effective length.
Effective length (Le),
When both ends of the column hinged (Le) = L
When both ends of the column fixed (Le) =
Calculation:
Given:
Buckling load for both ends hinged = 20kN and Le = L
Then, buckling load for the column when both ends fixed and Le =
Pe= 4 × 20 = 80 kN.
Euler's Theory of Buckling Question 2:
The piston rod of diameter 20 mm and length 700 mm in hydraulic cylinder is subjected to compressive force of 10 kN due to the internal pressure. The end conditions for the rod may be assumed as guided at the piston end and hinged at the other end. The Young’s modulus is 200 GPa. The factor of safety for the piston rod is
Answer (Detailed Solution Below)
Euler's Theory of Buckling Question 2 Detailed Solution
Concept:
Euler’s crippling load:
Assuming the guided end to be fixed and the other end is given as hinged. Euler’s crippling load formula is used to find the buckling load of long columns.
It is given by
Where E = Modulus of elasticity, I = moment of inertia, leff = Effective length of the column
The Effective length of the column depending on ends conditions is as follows:
End Condition |
Both ends hinged |
One end is fixed other free |
Both ends fixed |
One end was fixed and the other hinged |
Effective length (Le) |
L |
2L |
L/2 |
L/ √2 |
Calculations:
Given : Diameter (d) = 20 mm
Length (L) = 700 mm
Force (P) = 10 kN (compressive)
Assuming guided end to be fixed and other end given as hinged. The crippling load according to Euler’s equation.
Factor of safety
Euler's Theory of Buckling Question 3:
Which of the following is NOT an assumption in Euler’s theory?
Answer (Detailed Solution Below)
Euler's Theory of Buckling Question 3 Detailed Solution
Explanation:
According to Euler's column theory, the crippling load for a column of length L,
Where Leq is the effective length of the column.
The following assumptions are made in Euler's column theory:
- The column is initially straight and load is applied axially
- The cross-section of the column is uniform throughout its length
- The column material is perfectly elastic, homogeneous and isotropic and obeys Hooke’s law
- The length of the column is very large as compared to its lateral dimensions
- The direct stress is very small as compared to the bending stress
- The column will fail by buckling alone
- The self-weight of the column is negligible
Euler's Theory of Buckling Question 4:
Euler's formula is applicable for which type of columns?
Answer (Detailed Solution Below)
Euler's Theory of Buckling Question 4 Detailed Solution
Explanation:
Columns and Struts:
A structural member, subjected to an axial compressive force, is called a strut. A strut may be horizontal, inclined or even vertical. But a vertical strut, used in buildings or frames, is called a column.
According to Euler's column theory, the critical load (P) on the column for different types of end conditions is as follows:
Where Pe = Buckling load, Imin = Minimum of [Ixx & Iyy], L = Actual length of the column, α = Length fixity coefficient, n = End fixity coefficient
Le = αL and
Euler's formula holds good only for long columns.
The Length fixity coefficient and End fixity coefficient for the given end conditions are given in the following table:
S.No. |
End Conditions |
Length fixity coefficient (α) |
End fixity coefficient |
1. |
Both ends hinged |
1 |
1 |
2. |
One end fixed and the other end free |
2 |
|
3. |
Both ends fixed |
|
4 |
4. |
One end fixed and the other end hinged |
|
2 |
Additional Information
(1) The vertical column will have two moments of inertia (i.e. Ixx and Iyy). Since the column will tend to buckle in the direction of the least moment of inertia, therefore the least value of the two moments of inertia is to be used in Euler's formula.
(2) Euler's formula is given by
∵ I = Ak2,
Where A is the area and k is the least radius of gyration of the section
(3) The ratio (L/k) is known as the slenderness ratio.
(4) Sometimes, the columns whose slenderness ratio is more than 80, are known as long columns, and those whose slenderness ratio is less than 80 are known as short columns.
(5) Euler's formula holds good only for long columns.
(6) For short or long columns Rankine’s Formula is used.
Euler's Theory of Buckling Question 5:
In beam-columns or eccentric loaded columns, an elastic critical stress in compression fcc is
Where: E = Modulus of elasticity of steel
λ = Slenderness ratio in the plane of bending
Answer (Detailed Solution Below)
Euler's Theory of Buckling Question 5 Detailed Solution
Concept:
Elastic critical load in columns is given by Euler’s Formula which is,
Where,
Now, effective length (Le) for different end conditions in terms of actual length (L) are listed in the following table:
Support Conditions |
Effective length (Le) |
Both ends hinged/pinned |
Le = L |
One end hinged other end fixed |
Le = L/√2 |
Both ends fixed |
Le = L/2 |
One end fixed and other end free |
Le = 2L |
Now, moment of inertia can be expressed as,
∴ Elastic critical stress,
Euler's Theory of Buckling Question 6:
The crippling load taken by a column with both ends hinged is 100 kN. The crippling load taken by the same column with one end fixed and other end free will be:
Answer (Detailed Solution Below)
Euler's Theory of Buckling Question 6 Detailed Solution
Concept:
The maximum load at which the column tends to have lateral displacement or tends to buckle is known as buckling or crippling load. Load columns can be analysed with the Euler’s column formulas can be given as
End Condition |
Both ends hinged |
One end fixed other free |
Both ends fixed |
One end fixed and the other hinged |
Effective length (Le) |
L |
2L |
1/2 |
|
Calculation:
P1 = both ends hinged = 100 kN, P2 = one end fixed and other end free
P ∝ 1/Leq2
∴ P2 = 25 kN
Euler's Theory of Buckling Question 7:
For a long slender column of uniform cross section, the ratio of critical buckling load for the case with both ends hinged to the case with both ends clamped is
Answer (Detailed Solution Below)
Euler's Theory of Buckling Question 7 Detailed Solution
Concept:
Euler’s critical buckling load
Where, Imin = minimum area moment of Inertia, E = young’s modulus of elasticity, Le = Equivalent length = L ⋅ α
α for different loading conditions are different
Calculation:
Given:
Two columns,
both ends are fixed, Le = L × 0.5
both ends are hinged Le = L × 1
Euler's Theory of Buckling Question 8:
A steel column of rectangular section (15 mm × 10 mm) and length 1.5 m is simply supported at both ends. Assuming modulus of elasticity, E = 200 GPa for steel, the critical axial load (in kN) is ____ (correct to two decimal places).
Answer (Detailed Solution Below) 1.00 - 1.20
Euler's Theory of Buckling Question 8 Detailed Solution
Concept:
Long Column |
Critical Load |
Both ends are hinged |
|
One end fixed, and another end is free |
|
Both ends are fixed |
|
one end fixed & fixed and another end is hinged |
|
Calculation:
A steel column is simply supported at both ends means it is a case of both ends hinged:
Given: b = 15 mm, d = 10 mm, L = 1.5 m = 1500 mm, E = 200 GPa = 200 × 1000 MPa
Euler's Theory of Buckling Question 9:
The highest buckling load will be for ________.
Answer (Detailed Solution Below)
Euler's Theory of Buckling Question 9 Detailed Solution
Concept:
The maximum load at which the column tends to have lateral displacement or tends to buckle is known as buckling or crippling load. Load columns can be analysed with the Euler’s column formulas can be given as
- For both end hinged, n=1
- For one end fixed and other free, n=1/2
- For both end fixed, n=2
- For one end fixed and other hinged, n=√2
Effective Length:
Application:
nFixed-Fixed > nFixed-Hinged > nHing-Hing > nFixed-Free
PFixed-Fixed > PFixed-Hinged > PHing-Hing > PFixed-Free
So highest buckling load will be when both end fixed.
Euler's Theory of Buckling Question 10:
Which of the following assumptions is INCORRECT about the long column?
Answer (Detailed Solution Below)
Euler's Theory of Buckling Question 10 Detailed Solution
The following assumptions are made in the Euler’s column theory about long column:
- The column is initially perfectly straight, and the load is applied axially
- The cross-section of the column is uniform throughout its length
- The column material is perfectly elastic, homogeneous and isotropic and obeys Hooke’s law
- The length of the column is very large as compared to its lateral dimensions
- The direct stress is very small as compared to the bending stress.
- The column will fail by buckling alone
- The self-weight of the column is negligible