Latus Rectum MCQ Quiz in मराठी - Objective Question with Answer for Latus Rectum - मोफत PDF डाउनलोड करा

Last updated on Apr 8, 2025

पाईये Latus Rectum उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). हे मोफत डाउनलोड करा Latus Rectum एमसीक्यू क्विझ पीडीएफ आणि बँकिंग, एसएससी, रेल्वे, यूपीएससी, स्टेट पीएससी यासारख्या तुमच्या आगामी परीक्षांची तयारी करा.

Latest Latus Rectum MCQ Objective Questions

Top Latus Rectum MCQ Objective Questions

Latus Rectum Question 1:

The length of the latus-rectum of the ellipse, whose foci are (2, 5) and (2, –3) and eccentricity is  , is

Answer (Detailed Solution Below)

Option 4 :

Latus Rectum Question 1 Detailed Solution

Calculation:

 

Center C = 

Distance between foci: 

⇒ 2c = 

⇒ c = 4

Also e = a/c ⇒ a = c/e = 

Now ba− c25 − 16 9

⇒ b = 3

Length of latus rectum =  

Hence, the correct answer is Option 4.

Latus Rectum Question 2:

What is the sum of the major and minor axes of the ellipse whose eccentricity is 4/5 and length of latus rectum is 14.4 unit?

  1. 32 unit
  2. 48 unit
  3. 64 unit
  4. None of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 3 : 64 unit

Latus Rectum Question 2 Detailed Solution

Concept:

Standard equation of an ellipse:  (a > b)

Coordinates of foci = (± ae, 0)

Eccentricity (e) =  ⇔ a2e2 = a2 – b2

Length of latus rectum = 

Length of major axis =2a and Length of minor axis = 2b

 

Calculation: 

Here,  e = 4/5 =

Squaring both sides, we get

16/25 = 

∴ (b2 / a2) = 1 - 16/25 =  9/25 ....(1)

 

Latus rectus 2b2 / a = 14.4

⇒ b2 / a = 7.2

Puting above value in (1),

 7.2/ a = 9/25

⇒ a = 20

Now, b2 = 7.2 × 20 = 144

⇒ b = 12

 

Sum of major and minor axes = 2a + 2b

= 2(20) + 2(12)

= 64 

Hence, option (3) is correct.

Latus Rectum Question 3:

What is the length of the latus rectum of the ellipse 25x2 + 16y2 = 400 ?

  1. 25/2
  2. 25/4
  3. 16/5
  4. 32/5
  5. None of the above

Answer (Detailed Solution Below)

Option 4 : 32/5

Latus Rectum Question 3 Detailed Solution

Concept:

Equation

 (a > b)

  (a

Length of Latus rectum

 

Calculation:

25x2 + 16y2 = 400

Comparing, with standard equation: a = 4 ; b = 5

Since ( a

Latus Rectum Question 4:

The length of latus rectum of the ellipse 3x2 + y2 -12x + 2y + 1 = 0 is

  1. 12
  2. None of the above

Answer (Detailed Solution Below)

Option 3 :

Latus Rectum Question 4 Detailed Solution

Concept:

Standard Equation of ellipse: 

Length of latus rectum = 2b2/a, when a > b and 2a2/b, when a

Calculation:

3x2 + y2 -12x + 2y + 1 = 0

⇒ 3(x2 - 4x + 4) – 12 + (y2 + 2y + 1) = 0

⇒ 3(x – 2)2 – 12 + (y + 1)2 = 0

⇒ 3(x – 2)2 + (y + 1)2 = 12

                                  (Divide by 12)

∴ a2 = 22 and b2 = (2√3)2

Here a

So, length of latus rectum = 2a2/b

units

Hence, option (3) is correct.

Latus Rectum Question 5:

If the latus rectum of an ellipse is equal to half of the minor axis, then what is its eccentricity?

  1. 2 / √3
  2. 1 / √3
  3. √3 / 2
  4. 1 / √2
  5. None of the above

Answer (Detailed Solution Below)

Option 3 : √3 / 2

Latus Rectum Question 5 Detailed Solution

Concept:

The equation of ellipse is b)\)

length of Latus rectum of ellipse = 

Length of minor axis = 2b.

 eccentricity = 

Calculations:

Given, the latus rectum of an ellipse is equal to half of the minor axis.

Suppose, the equation of ellipse is 

length of Latus rectum of ellipse = 

Length of minor axis = 2b.

Given, the latus rectum of an ellipse is equal to half of the minor axis

⇒ 

⇒ 

If the equation of ellipse is  then eccentricity = 

⇒ 

⇒ e = 

If the latus rectum of an ellipse is equal to half of the minor axis, then what is its eccentricity e = 

 

Latus Rectum Question 6:

Let the foci of a hyperbola be (1, 14) and (1, –12). If it passes through the point (1, 6), then the length of its latus-rectum is :

  1. None of the above

Answer (Detailed Solution Below)

Option 3 :

Latus Rectum Question 6 Detailed Solution

Calculation

 

be = 13, b = 5

a2 = b2 (e2 – 1)

= b2 e2 – b2

= 169 – 25 = 144

Hence option 3 is correct

Latus Rectum Question 7:

Consider an ellipse, whose centre is at the origin and its major axis is along the x-axis. If its eccentricity is and the distance between its foci is , then the area (in sq. units) of the quadrilateral inscribed in the ellipse, with the vertices as the vertices of the ellipse, is.

Answer (Detailed Solution Below)

Option 3 :

Latus Rectum Question 7 Detailed Solution

The required area is in the shape of kite.

Area of kite

Now,


Latus Rectum Question 8:

Let the length of the latus rectum of an ellipse with its major axis along x-axis and center at the origin, be . If the distance between the foci of this ellipse is equal to the length of its minor axis, then when one of the following points lies on it?

Answer (Detailed Solution Below)

Option 2 :

Latus Rectum Question 8 Detailed Solution

and

so equation of ellipse is

Latus Rectum Question 9:

The length of latus rectum of the ellipse  is

  1. 10
  2. 12
  3. 15
  4. More than one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 3 : 15

Latus Rectum Question 9 Detailed Solution

Concept:

Standard equation of an ellipse:  (a > b)

  • Coordinates of foci = (± ae, 0)
  • Eccentricity (e) =  ⇔ a2e2 = a2 – b2
  • Length of Latus rectum = 

 

Calculation:

Given: 

Compare with the standard equation of an ellipse: 

So, a2 = 100 and b2 = 75

∴ a = 10

Length of latus rectum =  

Latus Rectum Question 10:

What is the length of the latus rectum of the ellipse 25x2 + 16y2 = 400 ?

  1. 25/2
  2. 25/4
  3. 16/5
  4. 32/5
  5. None of these

Answer (Detailed Solution Below)

Option 4 : 32/5

Latus Rectum Question 10 Detailed Solution

Concept:

Equation

 (a > b)

  (a

Length of Latus rectum

 

Calculation:

25x2 + 16y2 = 400

Comparing, with standard equation: a = 4 ; b = 5

Since ( a

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