Measurement of Frequency MCQ Quiz in தமிழ் - Objective Question with Answer for Measurement of Frequency - இலவச PDF ஐப் பதிவிறக்கவும்
Last updated on Mar 21, 2025
Latest Measurement of Frequency MCQ Objective Questions
Top Measurement of Frequency MCQ Objective Questions
Measurement of Frequency Question 1:
Capacitance can’t be measured by
Answer (Detailed Solution Below)
Measurement of Frequency Question 1 Detailed Solution
Explanation:
We can't measure the capacitance by using Cambell's bridge.
Carey foster bridge is used to measure the capacitance interms of standard mutual inductances.
Important Points
|
Type of Bridge |
Name of Bridge |
Used to measure |
Important |
|
DC Bridges |
Wheatstone bridge |
Medium resistance |
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Corey foster’s bridge |
Medium resistance |
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Kelvin double bridge |
Very low resistance |
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Loss of charge method |
High resistance |
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Megger |
High insulation resistance |
Resistance of cables |
|
AC Bridges |
Maxwell’s inductance bridge |
Inductance |
Not suitable to measure Q |
|
Maxwell’s inductance capacitance bridge |
Inductance |
Suitable for medium Q coil (1 |
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|
Hay’s bridge |
Inductance |
Suitable for high Q coil (Q > 10), slowest bridge |
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Anderson’s bridge |
Inductance |
5-point bridge, accurate and fastest bridge (Q |
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Owen’s bridge |
Inductance |
Used for measuring low Q coils |
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Heaviside mutual inductance bridge |
Mutual inductance |
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Campbell’s modification of Heaviside bridge |
Mutual inductance |
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De-Sauty’s bridge |
Capacitance |
Suitable for perfect capacitor |
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Schering bridge |
Capacitance |
Used to measure relative permittivity |
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|
Wein’s bridge |
Capacitance and frequency |
Harmonic distortion analyzer, used as a notch filter, used in audio and high-frequency applications |
Measurement of Frequency Question 2:
Wein-Bridge is commonly used for the measurement of
Answer (Detailed Solution Below)
Measurement of Frequency Question 2 Detailed Solution
Wein-Bridge and its Usage:
Definition: The Wein-Bridge is an electronic circuit predominantly used for the measurement of capacitance. It operates on the principle of balancing a bridge circuit, where the unknown capacitance is determined by comparing it with known components in the circuit. The bridge is named after Max Wien, who developed the concept for use in various measurement and oscillator applications.
Working Principle:
The Wein-Bridge consists of four arms in the form of resistors and capacitors. It is structured as follows:
- Two arms of the bridge contain resistors.
- The other two arms contain a combination of resistors and capacitors in series or parallel arrangements.
When an AC signal is applied to the bridge, the values of the resistors and capacitors are adjusted until the bridge reaches a balanced state. At this point, the output voltage across the bridge becomes zero, and the unknown capacitance can be calculated using the known values of the resistors and capacitors.
The balance condition for the Wein-Bridge is expressed as:
Z1 × Z4 = Z2 × Z3
Here, Z1, Z2, Z3, and Z4 are the impedances of the four arms of the bridge.
Advantages:
- High accuracy in capacitance measurement.
- Simple and reliable circuit design.
- Commonly used in laboratory instruments and audio frequency oscillators.
Applications:
- Measurement of unknown capacitance in electronic circuits.
- Used in audio frequency oscillators for generating sine waves.
- Implemented in filter design for signal processing applications.
Correct Option Analysis:
The correct option is:
Option 3: Capacitance
This is the correct answer because the Wein-Bridge is widely used for the measurement of capacitance. Its design specifically allows for precise determination of unknown capacitance values by balancing the bridge circuit and using known resistor and capacitor values. The working principle and formula for balancing the bridge make it a reliable tool for such measurements.
Measurement of Frequency Question 3:
In a digital frequency meter, the Schmitt trigger is used for
Answer (Detailed Solution Below)
Measurement of Frequency Question 3 Detailed Solution
Digital frequency meter: It is a general purpose instrument that displays the frequency of a periodic electrical signal to an accuracy of three decimal places. It counts the number events occurring within the oscillations during a given interval of time.
Block Diagram:
Working principle:
- The unknown frequency signal is fed to the Schmitt trigger. This signal may be amplified before being applied to Schmitt trigger.
- In a Schmitt trigger, the signal is converted into a square wave with a very fast rise and fall times, then differentiated and clipped.
- As a result, the output from a Schmitt trigger is a train of pulses, one pulse, for each cycle of the signal.
- The output pulses from the Schmitt trigger are fed to a start/stop gate when this gate opens (start), the input pulses pass through this gate and are fed to an electronic counter which starts registering the input pulses.
- When the gate is closed (stop), the input of pulses to counter ceases and it stops counting.
- The counter displays the number of pulses that have passed through it in the time interval between the start and stop. If this interval known, the pulse rate and hence the frequency of the input signal can be known.
The frequency of unknown signal is given by
f = N/t
where
N is the number of counts displayed by counter
t is the time interval between the start and stop of gate
Measurement of Frequency Question 4:
An ac bridge with terminal ABCD has in arm AB - a resistance of 1000 Ω in parallel with a capacitor of 0.6 μF, arm BC – a resistance of 500 Ω in series with a capacitance of 2 μF, arm CD – a resistance of 1200 Ω, arm DA – a pure resistance R. what is the value of R required to produced balance …. (in kΩ)
Answer (Detailed Solution Below) 1.5
Measurement of Frequency Question 4 Detailed Solution
R1 = 500 Ω, C1 = 2 μF
R2 = 1000 Ω C2 = 0.6 μF
R3 = 1200 Ω
R4 = R = ?
At balance condition
Z1Z4 = Z2Z3
Separating imaginary part we have
Putting the value we get
R = 1500 Ω = 1.5 kΩ
Measurement of Frequency Question 5:
Which of the following conditions are to be satisfied so that the common variable shaft of resistance R1 and R3 can be calculated in the frequency to measure the frequency of E under balance condition?
1) R1 = R3
2) C1 = C3
3) R2 = R4
4) R2 = 2R4
Select the correct answer given below
Answer (Detailed Solution Below)
1, 2, and 4
Measurement of Frequency Question 5 Detailed Solution
The given bridge is wein’s bridge under balance
If
And real part
⇒ R2 = 2 R4