Differentiation by taking log MCQ Quiz in తెలుగు - Objective Question with Answer for Differentiation by taking log - ముఫ్త్ [PDF] డౌన్లోడ్ కరెన్
Last updated on Mar 19, 2025
Latest Differentiation by taking log MCQ Objective Questions
Top Differentiation by taking log MCQ Objective Questions
Differentiation by taking log Question 1:
_________.
Answer (Detailed Solution Below)
Differentiation by taking log Question 1 Detailed Solution
Concept Used:
Power Rule:
Product Rule:
Chain Rule:
Logarithmic Differentiation
Calculation
Given:
⇒
Let
⇒
⇒
Using product rule:
⇒
At
⇒
⇒
⇒
⇒
⇒
∴ The value is
Hence option 3 is correct.
Differentiation by taking log Question 2:
If
Answer (Detailed Solution Below)
Differentiation by taking log Question 2 Detailed Solution
Given,
Taking
Differentiation by taking log Question 3:
If
Answer (Detailed Solution Below)
Differentiation by taking log Question 3 Detailed Solution
If
Taking log on both sides,
On differentiating w.r.t. x, we get
Differentiation by taking log Question 4:
If y = x
Answer (Detailed Solution Below)
Differentiation by taking log Question 4 Detailed Solution
Concept:
Product rule: (f.g)'(x) = f '(x).g(x) + f(x).g'(x)
Formula used :
- (ln x)' =
Calculation:
Given, y = x
Taking log on both sides,
ln y =
Differentiating both sides,
⇒
⇒
⇒
⇒
∴ The correct option is (5).
Differentiation by taking log Question 5:
If f(x) =
Answer (Detailed Solution Below)
Differentiation by taking log Question 5 Detailed Solution
Concept:
xn = nxn-1 sin x = cos x cos x = -sin x ex = ex ln x = (ax + b) = a tan x = sec2 x f(x)g(x) = f'(x)g(x) + f(x)g'(x) sin-1 x = tan-1 x =
Calculation:
Given: f(x) =
Taking log both sides, we get
⇒ log f(x) = log
⇒ log f(x) = sin x [log(log x)] (∵ log mn = n log m)
Let f(x) = y
Differentiating with respect to x, we get
Differentiation by taking log Question 6:
If xy = ex - y , then find the value of
Answer (Detailed Solution Below)
Differentiation by taking log Question 6 Detailed Solution
Calculation:
xy = ex - y
Taking log on both sides, we get
⇒ xy = log ex - y
⇒ y log x = (x - y) loge e
⇒ y log x = x - y [∵ loge e = 1]
⇒ ( 1 + log x)y = x
⇒ y =
Differentiating both sides , we get
=
=
Differentiation by taking log Question 7:
Differentiate x-ln x with respect to
Answer (Detailed Solution Below)
Differentiation by taking log Question 7 Detailed Solution
Concept:
Parametric Form:
If f(x) and g(x) are the functions in x, then
Calculation:
Let z = x-ln x
Taking log both sides, we get
ln z = ln x-ln x
ln z = - (ln x)2 (∵ ln mn = n ln m)
Differentiating with respect to x
Also y =
Taking log both sides, we get
ln y = ln
ln y = x2 ln e (∵ ln mn = n ln m)
ln y = x2 (∵ ln e = 1)
Differentiating with respect to x
The required result is
=
=
Differentiation by taking log Question 8:
If
Answer (Detailed Solution Below)
Differentiation by taking log Question 8 Detailed Solution
Concept:
log10(e) = 1 and
(log10(x))y = ylog(x)
Calculation:
Given:
For infinite terms, the above equation can be written as:
Taking log both sides
log(x) = (y + x)loge
log(x) = y + x
Differentiating both sides:
Hence option (2) is the solution.