A 40 µF capacitor is connected to a 200 V, 50 Hz ac supply. The rms value of the current in the circuit is, nearly :

This question was previously asked in
NEET 2020 Official Paper (Held On: 13 September, 2020)
View all NEET Papers >
  1. 2.5 A
  2. 25.1 A
  3. 1.7 A
  4. 2.05 A

Answer (Detailed Solution Below)

Option 1 : 2.5 A
Free
CT 1: Botany (Cell:The Unit of Life)
30.5 K Users
25 Questions 100 Marks 20 Mins

Detailed Solution

Download Solution PDF

Concept:

When a capacitor is connected to an AC source, alternating voltage charges and discharges the capacitor.

The rate of charging and discharging of the capacitor depends upon the frequency of the AC supply.

RMS values is the root mean square of instantaneous current values. RMS values of AC is greater than the average value.

Calculation:

Frequency, f = 100π

Voltage, V = 200 V

Capacitance, c = 40 × 10-6 F

ω = 2πf = 100π 

 rms value of the current in the circuit ,irms = cω εrms

εrms = 200 V

∴ irms = 200 × 40 × 10-6 × 2π × 50

= 2.5 A

Latest NEET Updates

Last updated on Jun 3, 2025

->NEET provisional answer key 2025 was made available on June 3, 2025 on the official website for the students to check.

->NEET 2025 exam is over on May 4, 2025.

-> The NEET 2025 Question Papers PDF are now available.

-> NTA has changed the NEET UG Exam Pattern of the NEET UG 2025. Now, there will be no Section B in the examination.

-> Candidates preparing for the NEET Exam, can opt for the latest NEET Mock Test 2025

-> NEET aspirants can check the NEET Previous Year Papers for their efficient preparation. and Check NEET Cut Off here.

More Alternating Current Questions

More Electromagnetic Oscillations and Alternating Current Questions

Get Free Access Now
Hot Links: teen patti live teen patti - 3patti cards game downloadable content teen patti octro 3 patti rummy teen patti star