Question
Download Solution PDFA and B are two heavy steel blocks. If B is placed on top of A, the weight increases by 60%. How much weight will reduce with respect to the total weight of A and B, if B is removed from the top of A?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
When B is placed on top of A, the weight increases by 60%.
This means that the weight of B is 60% of the weight of A.
Formula used:
Weight of B = 60% of Weight of A
Total weight of A and B = Weight of A + Weight of B
Percentage reduction in weight = (Weight of B / Total weight of A and B) × 100
Calculation:
Let the weight of A be WA.
Weight of B:
WB = 0.60 × WA
Total weight of A and B:
Wtotal = WA + WB
Wtotal = WA + 0.60 × WA
Wtotal = 1.60 × WA
Percentage reduction in weight when B is removed:
Percentage reduction = (WB / Wtotal) × 100
Percentage reduction = (0.60 × WA / 1.60 × WA) × 100
Percentage reduction = (0.60 / 1.60) × 100
Percentage reduction = (60 / 160) × 100
Percentage reduction = 37.5%
∴ The weight will reduce by 37.5% with respect to the total weight of A and B if B is removed from the top of A.
Shortcut Trick
Since the weight increases by 60% when B is placed on top of A.
60% = 3/5
So,
Weight will reduce to the total weight of A and B, if B is removed from the top of A:
⇒ 3/(3 + 5) × 100 = 3/8 × 100 = 37.5%
∴ The correct answer is option (4).
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