A diatomic gas, having CPR and CV R, is heated at constant pressure. The ratio dU ∶ dQ ∶ dW :

  1. 5 ∶ 7 ∶ 2
  2. 3 ∶ 7 ∶ 2
  3. 3 ∶ 5 ∶ 2
  4. 5 ∶ 7 ∶ 3

Answer (Detailed Solution Below)

Option 1 : 5 ∶ 7 ∶ 2
Free
JEE Main 04 April 2024 Shift 1
90 Qs. 300 Marks 180 Mins

Detailed Solution

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CONCEPT:

→The change in the internal energy is written as;

dU = nCvdT

Here dU is the internal energy, Cv is the specific heat at constant volume, and dT is the change in temperature.

The change in the heat energy is written as;

dQ = nCpdT

Here dQ is the heat energy, Cp is the specific heat at constant pressure, and dT is the change in temperature.

The change in work done is defined as;

dW = nRdT

Here we have R as the gas constant, and dT is the change in temperature.

CALCULATION:

Given: Specific heat at constant pressure 

and specific heat at a constant temperature 

The change in the internal energy is written as;

dU = nCvdT

⇒ dU =  dT    ----(1)

The change in the heat energy is written as;

dQ =  dT     ----(2)

The change in work done is defined as;

dW = nRdT     ----(3)

Now, on taking the ratio of (1), (2), and (3) we have;

dU ∶ dQ ∶ dW = 5 ∶ 7 ∶ 2

Hence, option 1) is the correct answer.

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