Question
Download Solution PDFA force of 400 N is required to open a process control valve. What is the area of diaphragm needed for a diaphragm actuator to open the valve with a control gauge pressure of 70 kPa?
This question was previously asked in
ESE Mechanical 2018 Official Paper
Answer (Detailed Solution Below)
Option 3 : 0.0057 m2
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ST 1: UPSC ESE (IES) Civil - Building Materials
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Detailed Solution
Download Solution PDFConcept:
Force required to open a valve = Pressure × Area of the diaphragm
Calculation:
Given F = 400 N and P = 70 kPa
F = P × A
400 = 70 × 103 × A
\(A = \frac{{400}}{{70 × 1000}} = 0.0057\;{m^2}\)
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