Question
Download Solution PDFA jet of water of 0.002 m2 area moving with a velocity of 15 m/s strikes on a series of blades moving with a velocity of 6 m/s. The force exerted on the blades will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Force exerted on the blades by a jet is given by
F = ρAv(v - u)
Calculation:
Given:
A = 0.002 m2, v = 15 m/s, u = 6 m/s, ρ = 1000 kg/m3
F = ρAv(v - u)
F = 1000 × 0.002 × 15(15 - 6)
F = 270 N
Last updated on Mar 26, 2025
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