Question
Download Solution PDFA relay is connected to a 400/5 A current transformer and set for 150%. The primary fault current of 2400 A needs a plug setting multiplier of
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Plug setting multiplier is the ratio of fault current and the product of plug setting and CT ratio.
Plug setting multiplier \(= \frac{{fault\;current}}{{plug\;setting \times CT\;ratio}}\)
Calculation:
Plug setting = relay setting × secondary CT current
= 1.5 × 5 = 7.5
CT ratio \(= \frac{{400}}{5} = 80\)
Plug setting multiplier \(= \frac{{2400}}{{7.5 \times 80}} = 4\)Last updated on May 28, 2025
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.