A symmetrical two-hinged parabolic arch when subjected to a uniformly distributed load on the entire horizontal span, is subjected to 

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BPSC AE Paper 5 (Civil Engineering) 2019 Official Paper
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  1. radial shear alone
  2. normal thrust alone
  3. normal thrust and bending moment
  4. normal thrust, radial shear and bending moment

Answer (Detailed Solution Below)

Option 2 : normal thrust alone
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In particular, if the 2-hinge arch has a parabolic shape and it is subjected to a uniform horizontally distributed vertical load, then only compressive forces will be resisted by the arch. Under these conditions, the arch shape is called a funicular arch because no bending or shear forces occur within the arch.

Bending moment, Mx = 0

Radial shear, Sx = 0

Normal thrust, Nx 0

Important Point:

Arches

Horizontal Thrust

Semicircular arch subjected to concentrated load (W) at Crown

Semicircular arch subjected to UDL (w/per unit length) over the entire span

Two hinged semi-circular arches subjected to uniformly varying load

Parabolic arch subjected to concentrated load (W) at Crown

Parabolic arch subjected to UDL (w/per unit length) over entire span

Two hinged parabolic arch subjected to uniformly distributed load on the half span

Two hinged parabolic arch subjected to varying distributed load on the full span

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