Question
Download Solution PDFA train is crossing a platform of length 200 meters in 45 seconds and man standing on the platform in 25 seconds. If a man moves in the direction of the train with a speed of 2 meters per second, then the time taken by the train to cross him is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Length of platform = 200 meters
Time taken to cross platform = 45 seconds
Time taken to cross a stationary man = 25 seconds
Speed of the man = 2 meters/second
Formula used:
Speed of train = Distance / Time
Relative speed = Speed of train - Speed of man (since both move in the same direction)
Time taken to cross the moving man = Length of train / Relative speed
Calculation:
Speed of train = Length of platform / Time taken to cross platform
⇒ Speed of train = 200 / 45
⇒ Speed of train = 40 / 9 meters/second
Length of train = Speed of train × Time taken to cross stationary man
⇒ Length of train = (40 / 9) × 25
⇒ Length of train = 1000 / 9 meters
Relative speed = Speed of train - Speed of man
⇒ Relative speed = (40 / 9) - 2
⇒ Relative speed = (40 / 9) - (18 / 9)
⇒ Relative speed = 22 / 9 meters/second
Time taken to cross the moving man = Length of train / Relative speed
⇒ Time = (1000 / 9) / (22 / 9)
⇒ Time = 1000 / 22
⇒ Time = 250 / 55
⇒ Time = 31(1/4) seconds
∴ The correct answer is option (2).
Last updated on Sep 26, 2023
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