An airplane has 6.1 m wing span and flies at 800 km/h. The vertical component of the magnetic flux density of the earth's magnetic field is 50 μT. Determine the EMF induced between the wing tips.

Question

Question

This question was previously asked in

MPPGCL JE Electrical 19 March 2019 Shift 2 Official Paper

Answer 1

Concept

The induced EMF in a conductor moving perpendicular to a magnetic field is given by:

\(e=Blv\)

where, e = EMF

B = Magnetic field density

l = Span

v = Velocity

Calculation

Given, Wing span (l) = 6.1 m

Speed (v) = 800 km/h = 222.22 m/s

Magnetic Flux Density (B) = 50 µT = 50 × 10^-6 T

e = (50 × 10^-6) × (6.1) × (222.22)

e = 67.7 mV