An international team has two boxers picked for an international sport event. What is the probability that both the boxers are men given that at least one of them is a man?

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  1. \(\frac{1}{2}\)
  2. \(\frac{1}{3}\)
  3. \(\frac{1}{4}\)
  4. \(\frac{1}{5}\)

Answer (Detailed Solution Below)

Option 2 : \(\frac{1}{3}\)
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Given:

The team has two boxers.

At least one of them is a man.

Formula:

\(Probability = \frac{Number \space of \space favourable \space outcomes}{Number \space of \space possible \space outcomes}\)

Explanation:

Let the two men be M1 and M2.

∵ it is given that at least one of them is a man.

∴ The possible combinations are "M1M2 or M1F or M2F"

∴ The probability that both of them are men given at least one is a man = 1/3

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