Question
Download Solution PDFAn isothermal cubical (10 m × 10 m × 10 m) blackbody at 200° C is suspended in air. The total radiation emitted by this body to its surroundings will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Q = ϵσAT4
Here A = surface area
∴ Surface area of cube = 6 × (side)2
Calculation:
Given:
Side of cube = 10 m, T = 200° C = 473 K
Now,
Q = ϵσAT4
∴ Q = 1 × 5.67 × 10-8 × 6 × (102) × (473)4
∴ Q = 1702 kW
Last updated on Jun 23, 2025
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