An oil of viscosity 10 poise flows between two parallel fixed plates which are kept at a distance of 50 mm apart. What is the rate of flow of oil between the plates if the drop of pressure in a length of 1⋅2 m be 0⋅3 N/cm² and the width of the plate is 200 mm?

Concept:

Volume Flow Rate in case of Laminar Flow through Parallel Plate is given by

\(Q = \frac{\Delta Ph^3b}{12\mu L}\)

where \(\Delta\)P = Pressure Difference, h = Distance between parallel plates, b = Width of Plate, L = Length of Plate, \(\mu \) = Viscosity

Calculation:

Given:

\(\Delta\)P = 0.3 N/cm² =  0.3 × 10⁴ N/m2, h = 50 mm = 0.05 m, b = 200 mm = 0.2 m, L = 1.2 m,  \(\mu \) = 10 Poise = 1 Pa.s

\(Q = \frac{0.3 \times 10^4 \times 0.05^3 \times 0.2 }{12 \times 1 \times 1.2}\)

Q = 5.208 × 10^-3 m³/sec = 5.208 L/s