An unbiased coin is tossed 3 times, if the third toss gets head what is the probability of getting at least one more head?

Answer (Detailed Solution Below)

Option 1 :
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Detailed Solution

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Concept: 

  • The number of ways for selecting r from a group of n (n > r) = nCr 
  • The probability of particular case

Calculation

If it is known that third toss gets head, the possible cases:

(H, H, H), (H, T, H), (T, H, H), (T, T, H)

∴ Total cases possible = 4

Total favourable cases = 3 [(H, H, H), (H, T, H), (T, H, H)]

So, required probability P = 

P = 

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