Question
Download Solution PDFAnswer the question according to the letter series given below
HDYSMWNBQPOCRTBLZVEGUF
Which two neighbours in the given arrangement are farthest in the alphabetical order?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven series: HDYSMWNBQPOCRTBLZVEGUF
Explanation :
The farthest pair of neighbours in the given arrangement will be: Greater the difference between the position values according to the English alphabetic series, the farther they will be.
Option - (1): U and F
HDYSMWNBQPOCRTBLZVEGUF
| Alphabet | Position value |
| U | 21 |
| F | 6 |
| Difference | (21 - 6) = 15 |
Option - (2): V and E
HDYSMWNBQPOCRTBLZVEGUF
| Alphabet | Position value |
| V | 22 |
| E | 5 |
| Difference | (22 - 5) = 17 |
Option - (3): B and Q
HDYSMWNBQPOCRTBLZVEGUF
| Alphabet | Position value |
| Q | 17 |
| B | 2 |
| Difference | (17 - 2) = 15 |
Option - (4): D and Y
HDYSMWNBQPOCRTBLZVEGUF
| Alphabet | Position value |
| Y | 25 |
| D | 4 |
| Difference | (25 - 4) = 21 |
Thus, out of all options "D and Y" are the farthest according to the English alphabetic series.
Hence, Option 4:D and Y is the correct answer.
Last updated on Jun 11, 2025
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