ABCD হল একটি সমদ্বিবাহু ট্রাপিজিয়াম যেমন AD||BC, AB = 5 সেমি, AD = 8 সেমি এবং BC = 14 সেমি। ট্র্যাপিজিয়ামের ক্ষেত্রফল (সেমি2 ) কত?

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SSC CGL Previous Paper 13 (Held On: 11 August 2017 Shift 1)
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  1. 36
  2. 44
  3. 88
  4. 144

Answer (Detailed Solution Below)

Option 2 : 44
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উপরের চিত্র থেকে AOB ত্রিভুজে পিথাগোরাসের উপপাদ্য ব্যবহার করে

⇒ AB2 = BO2 + OA2

⇒ 52 = 32 + OA2

⇒ OA = 4 সেমি যা ট্র্যাপিজিয়ামের উচ্চতার সমান

⇒ ক্ষেত্রফল = 1/2 × (উচ্চতা) × (সমান্তরাল বাহুর সমষ্টি)

⇒ ক্ষেত্রফল = 1/2 × 4 × (8 + 14) = 44

∴ ক্ষেত্রফল হল 44 সেমি2

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