যদি (4y - \(\frac{4}{y}\) ) = 13 হয়, তাহলে (y2 + \(\frac{1}{y^2}\) )-এর মান নির্ণয় করুন।

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SSC CGL 2023 Tier-I Official Paper (Held On: 24 Jul 2023 Shift 4)
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  1. \(12\frac{11}{16}\)
  2. \(10\frac{9}{16}\)
  3. \(12\frac{9}{16}\)
  4. \(8\frac{9}{16}\)

Answer (Detailed Solution Below)

Option 3 : \(12\frac{9}{16}\)
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প্রদত্ত

(4y - 4/y) = 13

ব্যবহৃত ধারণা

যদি (y - 1/y) = k হয়,

(y2 + 1/y2 ) = K2 + 2

গণনা

(4y - \(\frac{4}{y}\) ) = 13

পুরো সমীকরণটিকে 4 দ্বারা ভাগ করে পাই

⇒ (y - 1/y ) = 13/4

উভয়দিকে বর্গ করে পাই

⇒ (y2 + 1/y2 ) - 2 = 169/16  

⇒ (y2 + 1/y2 ) = 169/16 + 2

⇒ (y2 + 1/y2 ) = (169 + 3 2)/16

⇒ (y2 + 1/y2 ) = 201 /16

⇒ (y2 + 1/y2 ) = 12(9/16)

রাশিটির মান হল 12(9/16)

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