যদি a = 101, b = 102 এবং c = 103 হয়, তাহলে a2 + b2 + c2 − ab − bc − ca = _______.

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Answer (Detailed Solution Below)

Option 3 : 3
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প্রদত্ত

a = 101, b = 102 এবং c = 103

ব্যবহৃত সূত্র

1/2[(a - b)2 + (b - c)2 + (c - a)2] = a2 + b2 + c2 − ab − bc − ca

গণনা

a2 + b2 + c2 − ab − bc − ca = 1/2[(a - b)2 + (b - c)2 + (c - a)2]

a2 + b2 + c2 − ab − bc − ca = 1/2[(101 - 102)2 + (102 - 103)2 + (103 - 101)2]

a2 + b2 + c2 − ab − bc − ca = 1/2[12 + 12 + 22]

a2 + b2 + c2 − ab − bc − ca = 1/2[6]

a2 + b2 + c2 − ab − bc − ca = 3

মানটি 3

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