Question
Download Solution PDFযদি a = 101, b = 102 এবং c = 103 হয়, তাহলে a2 + b2 + c2 − ab − bc − ca = _______.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত
a = 101, b = 102 এবং c = 103
ব্যবহৃত সূত্র
1/2[(a - b)2 + (b - c)2 + (c - a)2] = a2 + b2 + c2 − ab − bc − ca
গণনা
⇒ a2 + b2 + c2 − ab − bc − ca = 1/2[(a - b)2 + (b - c)2 + (c - a)2]
⇒ a2 + b2 + c2 − ab − bc − ca = 1/2[(101 - 102)2 + (102 - 103)2 + (103 - 101)2]
⇒ a2 + b2 + c2 − ab − bc − ca = 1/2[12 + 12 + 22]
⇒ a2 + b2 + c2 − ab − bc − ca = 1/2[6]
⇒ a2 + b2 + c2 − ab − bc − ca = 3
মানটি 3
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