For perfect gas, the equation of state is              

This question was previously asked in
JKSSB JE Civil Jal Shakti 5 Dec 2022 Official Paper (Shift 2)
View all JKSSB JE Papers >
  1. p/ = (RT)2
  2. p/P = (RT)2
  3. P* = RT
  4. P/ = RT

Answer (Detailed Solution Below)

Option 4 : P/ = RT
Free
ST 1: JKSSB JE - Surveying
20 Qs. 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

Concept:

A hypothetical gas that obeys the law PV = nR̅T at all pressures and temperatures is called Ideal gas. There are two equations for Ideal Gas.

  • PV = nR̅T
  • PV = mRT,
  • P/ρ = RT

where,

P = Absolute pressure (Pa), V = Volume (m3), n = Number of moles of the gas 

Universal gas constant (8314 J/kg-mol.K), T = Absolute Temperature (K)

, M = Molecular weight of the gas

m = Mass of gas (kg) & ρ = Density of gas (kg/m3).

Latest JKSSB JE Updates

Last updated on Jun 23, 2025

-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27. 

-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been released on its official website. 

-> JKSSB JE exam will be conducted on 10th August (Civil), and on 27th July 2025 (Electrical).

-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering. 

-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025. 

-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025 

-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.

-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.

-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.

Hot Links: teen patti 500 bonus teen patti - 3patti cards game downloadable content teen patti gold downloadable content teen patti circle teen patti online game