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For what value of k, the system linear equation has no solution

(3k + 1)x + 3y - 2 = 0

(k2 + 1)x + (k - 2)y - 5 = 0

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HTET TGT Mathematics 2021 Official Paper
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  1. 1
  2. -1
  3. 2
  4. 6

Answer (Detailed Solution Below)

Option 2 : -1
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Detailed Solution

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Given:

a1 = 3k + 1

b1 = 3

c1 = -2

a2 = k2 + 1

b2 = k - 2

c2 = -5

Formula Used:

Calculation:      

By cross multiplication

⇒ (3k + 1)(k - 2) = 3(k2 + 1)

⇒ 3k2 - 6k + k - 2 = 3k2 + 3

⇒ -5k - 2 = 3

⇒ -5k = 5

∴ k = -1 

The correct option is 2 i.e. -1 

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