Question
Download Solution PDF20 kg द्रव्यमान वाले एक वस्तु को 20 सेकेंड में 5 m की ऊंचाई तक उठाया जाता है। तो आवश्यक शक्ति क्या होगी? (g=10m/s2)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
शक्ति:
- कार्य को करने की दर शक्ति कहलाती है।
- शक्ति की SI इकाई वाट है।
.जहाँ P = शक्ति, W = किया गया कार्य और t = समय
गणना:
दिया गया है m = 20 kg, h = 5 m, t = 20 सेकेंड और g = 10 m/sec2
- हम जानते हैं कि वजन m वाले एक निकाय को ऊंचाई h तक उठाने में किये गए कार्य को निम्न रूप में ज्ञात किया गया है,
⇒ W = mgh -----(1)
समीकरण 1 से,
⇒ W = 20 × 10 × 5 = 1000 J
- इसलिए आवश्यक शक्ति,
- अतः विकल्प 1 सही है।
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