यदि आपूर्ति आवृत्ति 50 Hz है तो 8-ध्रुव प्रत्यावर्तक की गति की गणना कीजिये।

This question was previously asked in
SSC JE Electrical 4 Dec 2023 Official Paper II
View all SSC JE EE Papers >
  1. 1500 rpm
  2. 1000 rpm
  3. 500 rpm
  4. 750 rpm

Answer (Detailed Solution Below)

Option 4 : 750 rpm
Free
Electrical Machine for All AE/JE EE Exams Mock Test
20 Qs. 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

संकल्पना:

एक तुल्यकालिक मशीन की तुल्यकालिक गति निम्न द्वारा दी जाती है

जहाँ f आवृत्ति है और P ध्रुवों की संख्या है।

एक तुल्यकालिक मशीन सदैव एक तुल्यकालिक गति से घूमती है।

गणना:

ध्रुवों की संख्या (P) = 8

आवृत्ति (f) = 50 Hz

तुल्यकालिक गति, 

Latest SSC JE EE Updates

Last updated on Jul 1, 2025

-> SSC JE Electrical 2025 Notification is released on June 30 for the post of Junior Engineer Electrical, Civil & Mechanical.

-> There are a total 1340 No of vacancies have been announced. Categtory wise vacancy distribution will be announced later.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

More Alternator and Synchronous Motors Questions

Hot Links: teen patti real cash teen patti flush teen patti real cash game