निम्न गुणोत्तर श्रेढ़ी (G.P.) का योगफल ज्ञात कीजिए। 

4/5, 4/25, 4/125, 4/625, ... n पदों तक 

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UP Police SI (दरोगा) Official PYP (Held On: 21st Nov 2021 shift 3)
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  1. 2/5(1-(1/5n)) 
  2. 5/4(1-(1/5n))
  3. (1-(1/5n))
  4. 4/5(1-(1/5n)) 

Answer (Detailed Solution Below)

Option 3 : (1-(1/5n))
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दिया गया है:

श्रेढ़ी 4/5 , 4/25 , 4/125 , 4/625 ,... से n पद तक है। 

प्रयुक्त सूत्र:

योग = a (1 - rn) / (1 - r )

जहाँ a = पहला पद और r = सार्व अंतर 

गणना:

सार्व अंतर (r) = (4/25) ÷ (4/5)

⇒ (1/5)

उपरोक्त सूत्र में r का मान रखने पर हमें प्राप्त होता है:

योग = \(\frac{4}{5}\)(1 - \(\frac{1}{5}\)n) / 1 - \(\frac{1}{5}\)

⇒ \(\frac{4}{5}\)(1- (\(\frac{1}{5}\))n) / \(\frac{4}{5}\)

⇒ (1 - (\(\frac{1}{5}\))n)

अतः सही उत्तर "(1 - (​\(\frac{1}{5}\))n)" है

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