400 और 500 के बीच की संख्याओं का योग ज्ञात कीजिए कि जब 8, 12 और 16 उन्हें विभाजित करते हैं, तो प्रत्येक स्थिति में 5 शेष बचता है।

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NTPC CBT-I (Held On: 4 Jan 2021 Shift 2)
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  1. 922
  2. 932
  3. 942
  4. 912

Answer (Detailed Solution Below)

Option 1 : 922
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RRB NTPC CBT-I Official Paper (Held On: 4 Jan 2021 Shift 1)
100 Qs. 100 Marks 90 Mins

Detailed Solution

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गणना:

संख्याएँ 8, 12 और 16 हैं जो संख्याओं को 400 और 500 के बीच विभाजित करती हैं और शेष 5 प्राप्त करती हैं।

विभिन्न संख्याओं के गुणज ज्ञात करने के लिए, हमें लघुतम समापवर्त्य का पता लगाना होगा।

8, 12, 16 का लघुतम समापवर्त्य

8 = 2³, 12 = 2² × 3, 16 = 2⁴

लघुतम समापवर्त्य = 2⁴ × 3 = 48

संख्या का स्वरूप = 48k + 5 (शेषफल)

400 और 500 के बीच की संख्या

सबसे छोटी संख्या = 48 × 9 + 5 = 437

सबसे बड़ी संख्या = 48 × 10 + 5 = 485

इसलिए,

संख्याओं का योग = 437 + 485

⇒ 922

∴ सही चुनाव विकल्प 1 है।

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