Question
Download Solution PDFयदि m और n दो धनात्मक वास्तविक संख्याएँ इस प्रकार है कि 9m2 + n2 = 40 और mn = 4 है, तो 3m + n का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया:
9m² + n² = 40
mn = 4
गणना:
9m² + n² = 40
दोनों पक्षों में 6mn जोड़ने पर, हम प्राप्त करते हैं:
9m² + n² + 6mn = 40 + 6mn
⇒(3m)² + n² + 2(3m)n = 40 + 6(4)
⇒(3m + n)² = 64
⇒ 3m + n = √64 = 8
इसलिए, अभीष्ट मान 8 है।
Last updated on Jul 8, 2025
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