How many four-digit natural numbers are there such that all of the digits are odd ?

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NDA 02/2022 Mathematics Official Paper (Held On 04 Sep 2022)
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  1. 625
  2. 400
  3. 196
  4. 120

Answer (Detailed Solution Below)

Option 1 : 625
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Detailed Solution

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Calculation:

Odd digits - 1, 3, 5, 7, 9

A four-digit number with all digits odd has 5 choices in the first position, and since digits can be repeated, there are 5 choices for the second, third, and fourth positions also.

So, the number of four-digit natural numbers such that all of the digits are odd = 5 × 5 × 5 × 5 = 625

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