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If the radius of a soap bubble is four times that of another, then the ratio of their pressure will be.

  1. \(1:4\)
  2. \(4:1\)
  3. \(16:1\)
  4. \(1:16\)

Answer (Detailed Solution Below)

Option 1 : \(1:4\)

Detailed Solution

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Calculation:

We know that 

\(\triangle P \propto \dfrac{1}{r}\)

\(\Rightarrow \dfrac{\triangle P_1}{\triangle P_2} = \dfrac{r_2}{r_1} = \dfrac{r}{4r} = \dfrac{1}{4}\)

Hence, the answer is \(1:4\).

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