If x, y, z are three consecutive positive integers, then log (1 + xz) is

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NIMCET 2015 Official Paper
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  1. log y
  2. log (y/2)
  3. log (2y)
  4. 2 log (y)

Answer (Detailed Solution Below)

Option 4 : 2 log (y)
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NIMCET 2020 Official Paper
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120 Questions 480 Marks 120 Mins

Detailed Solution

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Concept:

Logarithm Rule

log m= n log m

 

Calculations:

Let x, y, z are three consecutive positive integers.

⇒ y = x + 1 and z = y + 1

⇒ z = x + 2

Consider, log (1 + xz)

= log [1 + x(x+2)]

= log [1 + x2 + 2x]

= log (1 + x)2

= 2 log (1 + x)

= 2 log y

Hence, If x, y, z are three consecutive positive integers, then log (1 + xz) is 2 log y

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