If \(\rm a^{\frac{1}{3}}+b^{\frac{1}{3}}+c^{\frac{1}{3}}=0\), then the value of (a + b + c)3 = ?

This question was previously asked in
OSSC CGLRE (Mains) Exam (Mathematics) Official Paper (Held On: 23 July, 2023)
View all OSSC Combined Graduate Level Papers >
  1. 9abc
  2. 27abc
  3. 81abc
  4. 8abc

Answer (Detailed Solution Below)

Option 2 : 27abc
Free
Computer Awareness Mock Test for All-State Exams
29.3 K Users
10 Questions 10 Marks 6 Mins

Detailed Solution

Download Solution PDF

Given:

\(\rm a^{\frac{1}{3}}+b^{\frac{1}{3}}+c^{\frac{1}{3}}=0\)

Formula used:

If \(\rm a^{\frac{1}{3}}+b^{\frac{1}{3}}+c^{\frac{1}{3}}=0\), then

\(\rm a + b + c = 3\left(a^{\frac{1}{3}} \times b^{\frac{1}{3}} \times c^{\frac{1}{3}}\right)\)

Calculation:

\(\rm (a + b + c)^3 = \left[3\left(a^{\frac{1}{3}} \times b^{\frac{1}{3}} \times c^{\frac{1}{3}}\right)\right]^3\)

⇒ (a + b + c)3 = 27abc

∴ The value of (a + b + c)3 = 27abc

Latest OSSC Combined Graduate Level Updates

Last updated on Jun 12, 2025

-> OSSC CGL Final Merit List has been released on the official website. 

->The merit list consist the names of the candidates found suitable after the CV round.

->Earlier,The OSSC CGL Call Letter had been released for the Document Verification (Advt No.1249/OSSC).

-> Interested candidates registered from 29th November 2024 to 28th December 2024.

-> The recruitment is also ongoing for 543 vacancies (Advt. No. 129/OSSC). The Prelims was held on 20th October 2024 and thee Mains Exam will be scheduled in February/ March 2025.

-> The selection process includes Prelims, Mains, Skill Test, and Document Verification.

-> To score well in the exam, you may enhance your preparation by solving the OSSC CGL Previous Years' Papers.

-> Candidates can also attend the OSSC CGL Test Series which helps to find the difficulty level.

Get Free Access Now
Hot Links: teen patti real cash 2024 all teen patti teen patti online teen patti cash game