Question
Download Solution PDFIn a CBR test, the load sustained by a remoulded soil specimen at 5 mm penetration is 150 kg. The CBR value of the soil will be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
CBR test is strength test conducted on the soil by introducing surcharge load at the compaction rate of 1.25 mm per minute on a completely soaked soil sample passing through 20 mm sieve size.
\({\rm{CB}}{{\rm{R}}_{\rm{\delta }}} = \frac{{{{\rm{P}}_{\rm{\delta }}}{\rm{\;of\;soil}}}}{{{{\rm{P}}_{\rm{\delta }}}{\rm{\;of\;standard\;crushed\;aggregate}}}} \times 100\)
δ = displacement in mm
Pδ = Load corresponding to ‘δ’ settlement
Ps = Load for standard crushed aggregate:
At 5 mm penetration Standard load Ps = 2055 kg
At 2.5 mm penetration standard load Ps = 1370 kg
Calculation:
Given,
Sustained load at 5 mm penetration = 150 kg
\(CBR = \;\frac{{{\rm{Load\;carried\;by\;specimen}}}}{{{\rm{load\;carried\;by\;standard\;specimen}}}} \times 100\)
At 5 mm penetration, \(CBR = \;\frac{{150}}{{2055}} \times 100 = 7.29\% \)
Last updated on Jul 8, 2025
-> The BHEL Cut Off 2025 has been uploaded on July 8, 2025 at the official website
-> BHEL Engineer Trainee result has been released on July 8.
-> BHEL Engineer Trainee answer key 2025 has been released at the official website.
-> The BHEL Engineer Trainee Admit Card 2025 has been released on the official website.
->The BHEL Engineer Trainee Exam 2025 will be conducted on April 11th, 12th and 13th, 2025
-> BHEL Engineer Trainee 2025 Notification has been released on the official website.
-> A total of 150 Vacancies have been announced for various disciplines of Engineering like Mechanical, Electrical, Civil, etc.
-> Interested and eligible candidates can apply from 1st February 2025 to 28th February 2025.
-> The authorities has also released the BHEL Engineer Trainee Pattern
-> The BHEL Engineer Trainee Selection Process is divided into two stages namely Written Test and Interview.
-> The selected candidates for the Engineer Trainee post will get a salary range between Rs. 60,000 - Rs. 1,80,000.