Question
Download Solution PDFIn a Rutherford scattering experiment when a projectile of charge Z1 and mass M1 approaches a target nucleus of charge Z2 and mass M2, the distance of closest approach is r0. The energy of the projectile is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The distance of closest approach (r0) in a Rutherford scattering experiment is inversely proportional to the kinetic energy (K) of the projectile. Mathematically,
r0 = k / K
where k is a constant that depends on the charges of the projectile and the target nucleus.
For a projectile of charge Z1 and a target nucleus of charge Z2, the constant k is given by:
k = (Z1 Z2 e2) / (4 π ε0)
Thus, the energy of the projectile (K) can be written as:
K = (Z1 Z2 e2) / (4 π ε0 r0)
Calculation:
We are given the distance of closest approach r0 and need to determine the relationship between the energy of the projectile and the charges Z1 and Z2.
⇒ K = (Z1 Z2 e2) / (4 π ε0 r0)
From this formula, we can see that the energy K is directly proportional to the product of the charges Z1 and Z2.
∴ The energy of the projectile is directly proportional to Z1Z2.
Last updated on Jul 3, 2025
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