In a semiconductor crystal, if an energy band has a spread of 1 eV, and if there are 1022 discrete states in this band which are equally spaced in energy, then the difference between two consecutive discrete states will be:

This question was previously asked in
KVS TGT WET (Work Experience Teacher) 23 Dec 2018 Official Paper
View all KVS TGT Papers >
  1. 0.5 eV
  2. \(\rm \left(\frac{1}{22}\right)eV\)
  3. 10-22 eV
  4. 1022 eV

Answer (Detailed Solution Below)

Option 3 : 10-22 eV
Free
KVS TGT Mathematics Mini Mock Test
11.5 K Users
70 Questions 70 Marks 70 Mins

Detailed Solution

Download Solution PDF

Concept:

When many atoms are brought into close proximity as in a crystal, the discrete energy levels are replaced with bands of energy states separated by gaps between the bands as shown.

One may think of an energy band as a semi-continuum of a very large number of energy states.

F4 Vinanti Engineering 21.12.22 D13

Calculation:

Given;

Energy gap = 1 eV

No. of discrete states = 1022

Then;

The difference between two consecutive discrete states = 1/1022 = 10-22 eV

 

Latest KVS TGT Updates

Last updated on May 8, 2025

-> The KVS TGT Notiifcation 2025 will be released for 16661 vacancies.

-> The application dates will be announced along with the official notification.

-> Graduates with B.Ed or an equivalent qualification are eligible for this post.

-> Prepare with the KVS TGT Previous Year Papers here.

Get Free Access Now
Hot Links: teen patti circle teen patti list teen patti star