In case of welds using lap joints, the minimum lap should not be less than four times the thickness of the thinner part joined or t mm, whichever is more, where t (mm) is:

This question was previously asked in
DDA JE Civil Official Paper Shift 1 (Held on 23 April 2018)
View all DDA JE Papers >
  1. 10
  2. 30
  3. 40
  4. 20

Answer (Detailed Solution Below)

Option 3 : 40
Free
DDA JE Civil Full Mock Test
7 K Users
120 Questions 120 Marks 120 Mins

Detailed Solution

Download Solution PDF

Concept:

(i) For the size of the weld:

Minimum size of weld:

t (mm)

0 - 10

11-20

21-32

32-50

Smin(mm)

3

5

6

8

The minimum size of the weld is required to avoid stress concentration in welds.

Maximum size of weld:

Smax = t - 1.5 mm for pointed edge

\(= \frac{{3{\rm{t}}}}{4}\) for rounded edge

Where t is the thickness of the thicker member

The size of welded is limited to ensure uniform stress distribution.

(ii) Length of weld/lap of length

Lp min = 4t or 40 mm (as per WSM)

= 5t or 50 mm (as per LSM)

Latest DDA JE Updates

Last updated on May 28, 2025

-> The DDA JE Recruitment 2025 Notification will be released soon.

-> A total of 1383 vacancies are expected to be announced through DDA recruitment.

-> Candidates who want a final selection should refer to the DDA JE Previous Year Papers to analyze the pattern of the exam and improve their preparation.

-> The candidates must take the DDA JE Electrical/Mechanical mock tests or DDA JE Civil Mock tests as per their subject.

Get Free Access Now
Hot Links: online teen patti teen patti master download teen patti gold download apk teen patti real cash apk teen patti master gold apk