Question
Download Solution PDFJoule-Kelvin coefficient is given by [where T = absolute temperature, P = Pressure, s = Specific entropy, h = Specific enthalpy]
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Joule – Thomson coefficient:- When the gas in steady flow passes through a constriction, e.g. in an orifice or valve, it normally experiences a change in temperature. From the first law of thermodynamics, such a process is isenthalpic and one can usefully define a Joule – Thomson coefficient as
\(\mu = {\left( {\frac{{\partial T}}{{\partial P}}} \right)_H}\)
As a measure of the change in temperature which results from a drop in pressure across the construction.
- For an ideal gas, μ = 0, because ideal gases neither warm not cool upon being expanded at constant enthalpy.
- If μ is +ve, then the temperature will fall during throttling.
- If μ is -ve, then the temperature will rise during throttling.
Last updated on Jul 15, 2025
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