Question
Download Solution PDFABCD എന്ന ചതുരത്തിനുള്ളിലെ ഒരു ബിന്ദുവാണ് P. PA = 27 സെന്റീമീറ്റർ, PB = 21 സെന്റീമീറ്റർ, PC = 6 സെന്റീമീറ്റർ എന്നിങ്ങനെയാണെങ്കിൽ, PD (സെന്റീമീറ്ററിൽ) എത്രയാണ്?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFനൽകിയത്
PA = 27 സെന്റീമീറ്റർ, PB = 21 സെന്റീമീറ്റർ, PC = 6 സെന്റീമീറ്റർ
ഉപയോഗിക്കുന്ന ആശയം
PA2 + PC2 = PB2 + PD2
കണക്കുകൂട്ടൽ
⇒ 272 + 62 = 212 + PD2
⇒ 729 + 36 = 441 + PD2
⇒ PD2 = 324
PD = 18 സെന്റീമീറ്റർ
ഉത്തരം 18 സെന്റീമീറ്ററാണ്.
Last updated on Jun 2, 2025
-> The RRB NTPC Admit Card 2025 has been released on 1st June 2025 on the official website.
-> The RRB Group D Exam Date will be soon announce on the official website. Candidates can check it through here about the exam schedule, admit card, shift timings, exam patten and many more.
-> A total of 1,08,22,423 applications have been received for the RRB Group D Exam 2025.
-> The RRB Group D Recruitment 2025 Notification was released for 32438 vacancies of various level 1 posts like Assistant Pointsman, Track Maintainer (Grade-IV), Assistant, S&T, etc.
-> The minimum educational qualification for RRB Group D Recruitment (Level-1 posts) has been updated to have at least a 10th pass, ITI, or an equivalent qualification, or a National Apprenticeship Certificate (NAC) granted by the NCVT.
-> This is an excellent opportunity for 10th-pass candidates with ITI qualifications as they are eligible for these posts.
-> The selection of the candidates is based on the CBT, Physical Test, and Document Verification.
-> Prepare for the exam with RRB Group D Previous Year Papers.