Question
Download Solution PDF2 किलोच्या पिस्तूलमधून 25 ग्रॅमची गोळी 150 ms-1 च्या वेगाने आडवी उडवली जाते. तर पिस्तुलाचा अपेक्षित वेग किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF- 1.87 ms-1 हे योग्य उत्तर आहे.
Key Points
- गोळीचे वस्तुमान दिले, m1 = 25 g = 0.025 kg
- पिस्तुलचे वस्तुमान, m2 = 2 किलो
- गोळी (u1) आणि पिस्तूलचा प्रारंभिक वेग, u2 = 0
- गोळीचा अंतिम वेग, v1 = 150 ms-1
- समजा पिस्तूलचा वेग v आहे.
- गोळीबार करण्यापूर्वी पिस्तूल आणि गोळीचा एकूण संवेग शून्य असते (कारण दोन्ही शांत स्थितीत असतात)
- गोळीबार केल्यानंतर पिस्तूल आणि गोळीचा एकूण संवेग एवढी असेल
- =
- गणना केल्यानंतर, आपल्याला मिळेल,
- = (3.75 + 2v) kg ms-1
- गोळीबार केल्यानंतर एकूण संवेग = गोळीबार करण्यापूर्वी एकूण संवेग
- 3.75 + 2v = 0
- 2v = -3.75
- v = -3.75/2
- v = -1.875 m/s
- म्हणून, पिस्तूलचा वेग -1.875 m/s आहे.
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