Question
Download Solution PDF676 चौरस सेमी क्षेत्रफळ असलेली चौरस आकाराची तार वर्तुळाच्या आकारात वाकलेली आहे. वर्तुळाचा व्यास (सेमीमध्ये) शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
चौरस तारेचे क्षेत्रफळ = 676 चौरस सेमी
वापरलेली संकल्पना:
आकार बदलला तरीही तारेची लांबी समान राहते.
चौरसाचे क्षेत्रफळ = बाजू2
वर्तुळाचे परीघ = 2πr
वर्तुळाचा व्यास = 2r
जेथे,
r = त्रिज्या, d = व्यास
गणना:
चौरसाची बाजू = √676 सेमी 2 = 26 सेमी
येथे, तारेची लांबी = चौरसाची परिमिती
⇒ 4 × बाजू = 4 × 26 = 104 सेमी
ही लांबी वर्तुळाचे परिघ बनते,
म्हणून, 104 सेमी = 2πr
⇒ r = 104/(2 × π) = 16.54 सेमी
⇒ d = 2r = 2 × 16.54 = सेमी
∴ वर्तुळाचा व्यास अंदाजे
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