Question
Download Solution PDFΔABC ~ ΔPQR, ΔABC आणि ΔPQR चे क्षेत्रफळ अनुक्रमे 64 सेमी2 आणि 81 सेमी2 आहेत आणि AD आणि PT हे अनुक्रमे ΔABC आणि ΔPQR चे मध्यक आहेत. जर PT = 10.8 सेमी, तर AD = ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
ΔABC ~ ΔPQR
ΔABC चे क्षेत्रफळ = 64 सेमी2
ΔPQR चे क्षेत्रफळ = 81 सेमी2
PT = 10.8 सेमी
AD हा ΔABC चा मध्यक आहे.
PT हा ΔPQR चा मध्यक आहे.
संकल्पना:
दोन समान त्रिकोणांच्या क्षेत्रांचे गुणोत्तर हे संबंधित बाजू आणि मध्यकाच्या वर्गांच्या गुणोत्तरासारखे असते.
गणना:
⇒
⇒
⇒
⇒ AD =
∴ AD = 9.6 सेमी
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