Question
Download Solution PDF80% कार्यक्षम, 2kW (इनपुट) मोटरने 5 तास पीक लोडवर किती ऊर्जा वापरली आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
कार्यक्षमता (η) = (आउटपुट शक्ती)/(इनपुट शक्ती)
ऊर्जा = (शक्ती) (वेळ)
गणना:
आउटपुट शक्ती = (इनपुट शक्ती) (कार्यक्षमता) = 2 x 0.8
आउटपुट शक्ती = 1.6 kW
आउटपुट ऊर्जा = 1.6 x 5 = 8 kWhLast updated on Jun 11, 2025
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