If f(x2 + y2 + z2) = x + y + z – xy – 2yz + 4xz + 3xyz असल्यास, f(1 + 4 + 9) चे मूल्य शोधा.

  1. 22
  2. 20
  3. 26
  4. 24

Answer (Detailed Solution Below)

Option 1 : 22
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f(x2 + y2 + z2) = x + y + z – xy – 2yz + 4xz + 3xyz

f(1 + 4 + 9) = f(12 + 22 + 32)

⇒ 1 + 2 + 3 – (1 × 2) – 2(2 × 3) + 4(1 × 3) + 3(1 × 2 × 3)

⇒ 6 – 2 – 12 + 12 + 18

⇒ 22

∴ f(1 + 4 + 9) चे मूल्य 22 आहे

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