जर \( x=\sqrt{3018+\sqrt{36+\sqrt{169}}}\) , तर x चे मूल्य किती आहे?

Question

Question

This question was previously asked in

HTET PRT 2021 Official Paper

Answer 1

गणना:

\(\sqrt{}169 = 13\)

\(\sqrt{}36 = 6\)

प्रश्नाप्रमाणे:

\(x=\sqrt{3018+\sqrt{36+\sqrt{169}}}\)

\(x=\sqrt{3018+\sqrt{36+13}}\)

\(x=\sqrt{3018+7}\)

\(⇒ x=\sqrt{3025}\)

⇒ x = 55

योग्य पर्याय 3 आहे. म्हणजेच 55