Question
Download Solution PDFΔABC मध्ये, लंब AG, BH आणि CI हे एकमेकांना O येथे भेटतात. जर ∠B = 44°, ∠C = 66°, ∠BOC चे मूल्य किती?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
ΔABC मध्ये, लंब AG, BH आणि CI हे एकमेकांना O येथे भेटतात.
∠B = 44°, ∠C = 66°
वापरलेली संकल्पना:
त्रिकोणाच्या तीनही कोनांची बेरीज 180° असते.
लंब ज्या बिंदुला भेटतात त्याला लंबसंपात म्हणतात.
दिलेल्या बाजूमुळे लंबसंपातपाशी तयार झालेला कोन = [180° - (दिलेल्या बाजूचा विरुद्ध कोन)]
गणना:
त्रिकोणाच्या बेरीज गुणधर्मानुसार,
∠A + ∠B + ∠C = 180°
⇒ ∠A + 44° + 66° = 180°
⇒ ∠A = 180° - 110°
⇒ ∠A = 70°
दिलेल्या बाजूमुळे लंबसंपातपाशी तयार झालेला कोन = [180° - (दिलेल्या बाजूचा विरुद्ध कोन)]
⇒ ∠BOC = 180° - 70° = 110°
∴ ∠BOC = 110°.
Last updated on Jul 3, 2025
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