Polar plot of transfer function is

G(jω) = 

This question was previously asked in
UPPSC AE Electrical 29 May 2022 Official Paper I
View all UPPSC AE Papers >

Answer (Detailed Solution Below)

Option 3 :
Free
UPPSC AE सामान्य हिन्दी Mock Test
20 Qs. 60 Marks 20 Mins

Detailed Solution

Download Solution PDF

Polar plot:

The polar plot is a plot, that is drawn between the magnitude and the phase angle of G(jω) by varying ω from zero 0 to ∞.

Given, G(jω) = 

|G(jω)| = 

∠G(jω) = -90° - tan-1(ωT1

ω 

G(jω)| = 

∠G(jω) = -90° - tan-1 (ωT1)

0

 ∞ 

-90° 

∞ 

 0

-180° 

 

Latest UPPSC AE Updates

Last updated on Jun 13, 2025

-> UPPSC AE Mains Exam 2025 registration has been started. 

-> UPPSC AE Mains registration window is available till June 27. However, last date to send the documents is July 4. 

-> UPPSC AE result 2025 has been released for Prelims exam. 

-> UPPSC AE Answer Key 2025 has been uploaded on 23rd April 2025.

-> UPPSC AE Exam was conducted 20th April 2025 on its official website.

-> The UPPSC AE Exam Date 2025 has been released.

-> The Prelims & Mains exam will be conducted on 20th April & 28th September 2025 respectively.

-> A total of 604 vacancies have been released.

-> The applications must be submitted online between 17th December 2024 to 17th January 2025.

-> The selection process includes a written exam, interview, and document verification.

-> Candidates with a BE/B.Tech degree in the relevant discipline, between 21 to 40 years of age are eligible for this post.

More Frequency Response Analysis Questions

Hot Links: lotus teen patti teen patti refer earn teen patti wink