Power dissipated in 10 Ω resistor will be:

Question

Question

This question was previously asked in

KVS TGT WET (Work Experience Teacher) 23 Dec 2018 Official Paper

Answer 1

Concept:

Power dissipated in a resistor is given by;

P = VI = I²R = V²/R

Where;

V → Voltage across resistor

I→ Current through resistor

R→ Resistance

Calculation:

In the circuit 20Ω and 60Ω are in parallel;

Then;

I = (120-65)/(10+15+30) = 1 A

Therefore;

Power dissipated across 10 Ω resistor = I²R = 1 × 10 = 10 W