If a2 + b2 + c2 - ab - bc - ca = 0, then a ∶ b ∶ c is :

This question was previously asked in
Haryana CET Previous Year Paper (Held On: 6 Nov 2022 Shift 2)
View all Haryana CET Papers >
  1. ∶ 2 ∶ 1
  2. ∶ 1 ∶ 1
  3. ∶ 1 ∶ 2
  4. ∶ 1 ∶ 1
  5. Not attempted 

Answer (Detailed Solution Below)

Option 4 : ∶ 1 ∶ 1
Free
Haryana CET Full Test 1
47.2 K Users
100 Questions 100 Marks 105 Mins

Detailed Solution

Download Solution PDF

Given :

a2 + b2 + c2 - ab - bc - ca = 0

Solution :

Here we have 3 variables and only one equation .

Note:  To solve these type of question we assume the value of any 2 variables.

Let assume that b = 1 and c = 1

⇒ a+ 1 + 1 - a - 1 - a = 0

⇒ a2 + 1 - 2a = 0

⇒ ( a - 1 )2 = 0                    [ ∵  ( A + B )2 = A2 + B2 + 2AB ]

Now a = 1

Now we have a = 1, b = 1 and c = 1

So a : b : c = 1 : 1 : 1

Hence the correct answer is "1 : 1 : 1".

Latest Haryana CET Updates

Last updated on Jul 10, 2025

->HSSC CET Exam Date 2025 is 26th and 27th July 2025.

->The Haryana HSSC CET 2025 Exam will be held for two days in 4 shifts.

->Earlier, Haryana CET Group C Notice for EWS Certificate was out. A valid format of EWS Certificate has been given in the Notice.

-> Haryana CET Group C Notification 2025 was out on 26th May 2025.

-> The minimum educational qualification to apply for the Common Eligibility Test is 10+2/equivalent 

-> Candidate applying for CET should not be less than 18 years of age and not more than 42 years.

-> Aspirants must go through the Haryana CET Previous Years’ Papers to understand the need for the exam and prepare for the exam in the right direction.

Get Free Access Now
Hot Links: teen patti real all teen patti teen patti 100 bonus teen patti 51 bonus