Question
Download Solution PDFPT అనేది O మరియు OP = 17 సెం.మీ మరియు OT = 8 సెం.మీ ఉన్న వృత్తం యొక్క Tకి టాంజెంట్ అయితే, టాంజెంట్ లైన్ సెగ్మెంట్ PT పొడవును కనుగొనండి.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చినవి:
PT అనేది వృత్తానికి టాంజెంట్, దీని కేంద్రం O
OP = 17 సెం.మీ
OT = 8 సెం.మీ
ఉపయోగించిన సూత్రము:
పైథాగరస్ సిద్ధాంతం: లంబకోణ త్రిభుజంలో, కర్ణం సమానం -
OP2 = OT2 + TP2
గణన:
ఇది, టాంజెంట్ TP యొక్క పొడవు సమానంగా ఉంటుంది:
TP2 = OP2 - OT2
TP2 = (17)2 - (8)2
TP2 = 289 - 64
TP2 = 225
TP = √225 = 15
∴ టాంజెంట్ సెగ్మెంట్ PT పొడవు 15 సెం.మీ.కి సమానం.
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